# Principles of Programming

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MIS501 Principles of Programming
Assessment 3 – Business Case Study Final Solution
Case Study
Impressed by your programs implemented in Assessment 2, the Subject Coordinator of COMP101 has
asked to develop a program solving a variation of Task 2 in Assessment 2 but this time you need to
implement it using the Object Orientated Programming (OOP) paradigm. Read the following case with
a
fresh mind, as it is NOT the same as the one in Assessment 2.
You recall from Assessment 2 that COMP101 is offered in both the Bachelor of Information Technology
(BIT) degree and the Diploma of Information Technology (DIT) course at ABC University. In Assessment
2, you did not distinguish these two groups of students in calculating their grade letters. However, in
this assessment, you are required to consider the different approaches used in calculating the grade
letters for students in these two programs.
Final mark for both BIT and DIT students
Recall the assessment regime used in COMP101 Foundations of Computer Systems. It has three
assessments with the following weightings.

 Assessment Number Assessment Type Assessment Weighting 1 Lab exercise 20% 2 Report 40% 3 Final examination 40%

The assessment regime in COMP101 applies to both BIT and DIT students. Upon completion of all
three assessments, both groups of students will receive a final mark that is calculated in the following
way.
Each assessment is marked out of 100 and the mark for each assessment may be a decimal number
with at most two decimal points (e.g., 68, or 68.5, or 68.45). The final mark for COMP101 is the
weighted sum of all three assessments, rounded
up to the nearest integer. For example, Student A
received 75.67/100, 45.8/100, 32/100 for Assessment 1, 2 and 3 respectively. Their final mark for
COMP101 is 47 (46.254 rounded
up to the nearest integer).
75.67 × 20% + 45.8 × 40% + 32 × 40% = 46.254
For simplicity, we will use a bracket that consists of three numbers to denote the marks of a student’s
three assignments in order. For example, (75.67, 45.8, 32) denote a student who received 75.67/100
for the first assessment, 45.8/100 for the second, and 32/100 for the third.
Once the final mark is calculated, it is used to determine the interim grade. However, the way the
interim grade is calculated differs depending on the type of students.

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Interim Grade Letter for BIT students
The Assessment Policy and Procedures of ABC University stipulates the following rules for determining
the interim grade letter for undergraduate students (including BIT students). The range in the Final
mark column includes the numbers on both ends.

 Final mark Interim grade letter Description 85 – 100 HD High Distinction 75 – 84 D Distinction 65 – 74 C Credit 50 – 64 P Pass 45 – 49 F or SE or SA Fail or Supplementary Assessment or Supplementary Exam 0 – 44 F or AF Fail or Absent Fail

BIT students whose final mark is between 0 and 44 (inclusive) may be awarded an F (Fail) or an AF
(Absent Fail). If two or more assessments are awarded zero and the final mark is between 0 and 44
(inclusive), the student will be awarded an AF (Absent Fail), otherwise they are awarded an F (Fail).
For example, BIT students with (0, 100, 0) should be awarded an AF because their final mark is 40, and
two assessments are marked zero. However, BIT students with (100, 50, 0) should be awarded an F
because although their final mark is 40, they only have one assessment awarded zero.
BIT students who have marginally failed, that is, their final mark is between 45 – 49 (inclusive), may
be awarded an F (Fail) or Supplementary Exam (SE) or Supplementary Assessment (SA). If a student’s
final mark is between 45 – 49, they will receive an F (Fail) unless they satisfy
all the following
conditions:
o Their final mark is between 45 – 49 (inclusive).
o They do not have any assessment marked zero.
o They only failed (i.e., less than 50) one assessment.
BIT students whose final mark is between 45 – 49 will receive an SE or SA if they satisfy all the
conditions above. If the assessment they failed is Assessment 1 or Assessment 2, they will receive an
SA and they will be given an opportunity to attempt a supplementary assessment. If the assessment
they failed is Assessment 3, they will receive an SE and they will be given an opportunity to sit a
supplementary exam.
For example, BIT students with (40, 100, 0) will receive an F (Fail) because although their final mark is
48 (i.e., between 45 – 49), they have one assessment marked zero (Assessment 3). Students with (10,
100, 10) will equally be awarded an F (Fail) because although their final mark is 46 (i.e., between 45 –
49), they have failed more than one assessment (Assessment 1 and Assessment 3). Students with (50,
50, 40) will be awarded an SE because their final mark is 46 (i.e., between 45 – 49) and satisfy all the
three conditions above. The only failed assessment is Assessment 3, and they will be given an
opportunity to sit a supplementary exam.

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Interim Grade Letter for DIT students
For diploma level students (including DIT students), the calculation of interim grade is much more
straightforward as shown in the following table.

 Final mark Interim grade letter Description 50 – 100 CP Competent 0 – 49 NYC Not yet competent

Students who received an NYC (not yet competent) will be provided with an opportunity to resubmit
all three assessments.
A couple of weeks after the Release of Grade date, all supplementary assessments and exams have
been finalised for BIT students. For DIT students who have been given an opportunity to resubmit
their assessments, their submissions have been marked and finalised. All the interim grade letters now
need to be converted to a final grade letter, that is, the grade letter that appear on students’
transcript.
Final Grade Letter – BIT students
For HD (High distinction), D (Distinction), C (Credit), P (Pass) and F (Fail), they will not be converted as
they themselves are final grade letters. For SA and SE, they will be converted to either a SP
(Supplementary Pass) or F (Fail). If the student who have been awarded an SA or SE passed the
supplementary assessment or supplementary exam (that is, they achieved no less than 50/100), their
grade letter will be converted to SP (Supplementary Pass), otherwise it will be converted to F (Fail).
For AF (Absent Fail), it will be converted to F (Fail).
Each final grade letter carries some grade point value as detailed in the table below.

 Final grade letter Grade point value HD 4.0 D 3.0 C 2.0 P 1.0 SP 0.5 F

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Final Grade Letter – DIT students
For CP (Competent), it does not need to be converted as it is a final grade letter itself. For NYC (Not
yet competent), it will be converted to either a CP (Competent) or NC (Not competent). For students
who received NYC (Not yet competent) and resubmitted all three assessments, if the final mark of the
resubmitted assessments is no less than 50 marks, then NYC (Not yet competent) will be converted to
CP (Competent), otherwise, it will be converted to NC (Not competent). At this stage, if the final mark
of the resubmitted assessments is no less than 50 marks, then the student’s all assessment marks and
final mark are determined by the resubmission of assessments, that is, the information of the marks
of their first submissions will be discarded.
Each final grade letter carries some grade point value as detailed in the table below.

The program you need to implement
The Subject Coordinator (the user) will use your program to manage students’ grade. This section
describes several scenarios in which the subject coordinator (the user) can interact with your program.
Once your program starts, it should prompt the user the following main menu, allowing the user to
choose any one of the options:
>>>
Choose one of the following options:
>>> 1 – Enter student grade information
>>> 2 – Print all student grade information
>>> 3 – Print class performance statistics
>>> 4 – Exit
You should read in the user choice – an integer between 1 and 4. Your program should detect illegal
inputs (that is, inputs that should not be allowed, e.g. letter ‘a’ or number 6), and prompt to the user
that they should only enter a whole number between 1 and 4. For the rest part of your program, you
should always verify input validity.
Option 1 – Enter student grade information
If the user chooses option 1, your program should then prompt the user with the following Option 1
:
>>>
Choose one of the following options:
>>> 1.1 – Enter a BIT student information
>>> 1.2 – Enter a DIT student information
>>> 1.3 – Go back to the main menu
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You should read in the user choice: 1.1, 1.2 or 1.3.
Option 1.1 – Enter a BIT student information
If the user chooses 1.1, your program should then allow the user to enter the following information
Student ID (A capital letter ‘A’ followed by 8 digits)
Student’s name
Student’s assessment marks (separated by comma)
[Optional] Student’s SE/SA mark (If your program detects that the student would have been
given an SE or SA, your program should then ask for their supplementary assessment or
supplementary exam mark).
Your program will then prompt the user
>>>
Enter student ID:
>>> A12345678
>>> Enter student name:
>>> Josh Hutter
>>> Enter student assessment marks (separated by comma):
>>> 40,100,0
>>> Choose one of the following options:
>>> 1.1 – Enter a BIT student information
>>> 1.2 – Enter a DIT student information
>>> 1.3 – Go back to the main menu
Another example:
>>>
Enter student ID:
>>> A87654321
>>> Enter student name:
>>> Mary Podbury
>>> Enter student assessment marks (separated by comma):
>>> 50,50,40
>>> What is this student’s supplementary exam mark:
>>> 67
>>> Choose one of the following options:
>>> 1.1 – Enter a BIT student information
>>> 1.2 – Enter a DIT student information
>>> 1.3 – Go back to the main menu
Option 1.2 – Enter a DIT student information
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If the user chooses 1.2, your program should then allow the user to enter the following information
Student ID (A capital letter ‘A’ followed by 8 digits)
Student’s name
Student’s assessment marks (separated by comma)
[Optional] Student’s resubmission assessment marks (If your program detects that the
student would have been given an NYC, your program should then ask for their resubmission
marks).
Your program will then prompt the user
>>>
Enter student ID:
>>> A12345678
>>> Enter student name:
>>> Josh Hutter
>>> Enter student assessment marks (separated by comma):
>>> 90,100,100
>>> Choose one of the following options:
>>> 1.1 – Enter a BIT student information
>>> 1.2 – Enter a DIT student information
>>> 1.3 – Go back to the main menu
Another example:
>>>
Enter student ID:
>>> A87654321
>>> Enter student name:
>>> Mary Podbury
>>> Enter student assessment marks (separated by comma):
>>> 50,50,40
>>> What is this student’s resubmission marks (separated by comma):
>>> 90,100,100
>>> Choose one of the following options:
>>> 1.1 – Enter a BIT student information
>>> 1.2 – Enter a DIT student information
>>> 1.3 – Go back to the main menu
Option 1.3 – Go back to the main menu
If the user chooses 1.3, your program will then prompt the user the main menu and await user’s
choice.

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Option 2 – Print all student grade information
If the user chooses option 2, your program should then prompt the user with the following Option 2
:
>>>
Choose one of the following options:
>>> 2.1 – Print all student grade information ascendingly by final mark
>>> 2.2 – Print all student grade information descendingly by final mark
>>> 2.3 – Go back to the main menu
You should read in the user choice: 2.1, 2.2 or 2.3.
Option 2.1 – Print all student grade information ascendingly by final mark
If the user chooses option 2.1, your program should print student ID, student name, student type (BIT
or DIT), student final mark and student final grade letter separated by a tabular character. They are
sorted ascendingly by final marks. Your program will then prompt the user with

 >>> A47586734 Mary Lastname DIT 95 CP >>> A12345678 Josh Lastname BIT 90 HD >>> A85769234 Lovejeet Singh BIT 34 F

>>> Choose one of the following options:
>>> 2.1 – Print all student grade information ascendingly by final mark
>>> 2.2 – Print all student grade information descendingly by final mark
>>> 2.3 – Go back to the main menu
Option 2.2 – Print all student grade information descendingly by final mark
If the user chooses option 2.2, your program should print student ID, student name, student type (BIT
or DIT), student final mark and student final grade letter separated by a tabular character. They are
sorted descendingly by final marks. Your program will then prompt the user with

 >>> A85769234 Lovejeet Singh BIT 34 F >>> A12345678 Josh Lastname BIT 90 HD >>> A47586734 Mary Lastname DIT 95 CP

>>> Choose one of the following options:
>>> 2.1 – Print all student grade information ascendingly by final mark
>>> 2.2 – Print all student grade information descendingly by final mark
>>> 2.3 – Go back to the main menu
Option 2.3 – Go back to the main menu
If the user chooses 2.3, your program will then prompt the user the main menu and await user’s
choice.

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Option 3 – Print class performance statistics
If the user chooses option 3, your program will output the following class performance statistics:
o Number of students: This number shows the total number of students that the user typed in.
o Number of BIT students: This number shows the total number of students that the user typed
in.
o Number of DIT students:
o Student pass rate: The percentage of students who received a final grade letter of HD, D, C, P
SP or CP, that is,
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